radius of curvature of two faces of double convex lens is 10 cm 15 cm and its refractive 1.50 find its focal length of a lens
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by lens maker formulae
f=(n-1)(1/R1-1/R2)
R2 will be negative therefore the formula will become
f=(n-1)(1/R1+1/R2)
f=(n-1)(1/R1-1/R2)
R2 will be negative therefore the formula will become
f=(n-1)(1/R1+1/R2)
Answered by
1
Since the given lens is a double convex lens;R1 will be positive whereas R2 will be negative.
R1=10cm
R2=15cm
n=1.5cm
f=??
Using the lens maker formula
1/f=(n-1)(1/R1-1/R2)
1/f=(1.5-1)[1/10+1/15]
After solving the equation u will be getting the focal length as 12cm
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