Radius of the circle 2x^2+2y^2-x=0
B. (1/4,0)
D. (-1/2,0)
A. (-1.0)
C. (1,0)
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2
Answer:
I think c is the right answer ...xd
Answered by
1
Answer:
2x^2 + 2y^2 - x = 0
Given the equation of the circle is 2x^2 + 2y^2 - x = 0 or, x^2 + y^2 - x2 = 0 or, x^2 - 2.x. 14 + 14^2 + y^2 = 14^2 or, (x - 14 )^2 + y^2 = 14^2.
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