Question

Radius of the earth is 6.4 × 10^3 and value of acceleration due to gravity on its surface is 9.8 m/s^2. Find the value of acceleration due to gravity produced on a meteor at a distance of 9850 meter from the earth surface

Answer 1

Answer:

given :- radius of the earth = 6.4×10^3

Acceleration due to gravity on its surface =9.8m/s^2

solution :- radius of the earth

_____________________

acceleration due to gravity

= 6.4 × 10^3

_________

9.8 × 10^3

= 6.4 × 9.8

= 62.72

= the answer is 62.72m/s^2