Chemistry, asked by medineseckin5063, 1 year ago

Radius of the second bohr orbit of a singly ionised helium atom is

Answers

Answered by Anonymous
0

Answer:

actually

radius =(0.529) (n^2/z) A

where n is orbit number

z is atomic number

now

radius=(0.529)(9/2) A

=2.385A

Explanation:

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