Question

Radius of the wheel of a cart is 42 cm. An iron-plate is to be ï¬xed on the edge of wheel, then how much cm long plate is needed? If cost of 10 plate is Rs.20, then what is the total cost of iron-plate?

Answer 1

Answer: 528 rupee

Step-by-step explanation: perimeter of circle = 2πr

= 2×22/7×42

= 264

Now cost

264×20/10=528

Answer 2

Answer:

264cm long plate is needed,Cost is 528Rs.

Step-by-step explanation:

In this question,

We have been given that  

Radius of the wheel of a cart is 42cm,an iron plate is fixed on the edge of the wheel.

We need to find how much length of plate is required.

According to the question,

We know that circumference of the circle is given by = 2πr

where r is the radius of the circle and π = $\frac{22}{7}$

Therefore circumference of the wheel cart is = $2\times \pi\times r$

Circumference of the circle is = $2\times \frac{22}{7}\times 42$

Circumference of the circle is = 264cm

cost of 10cm long plate is Rs.20

Then cost 1cm long plate is Rs.2

Hence,Cost of 264cm long plate = 264 × 2

                                                     = 528Rs.