Math, asked by amzadchoudhary555, 4 months ago

Ragini deposited 2400 rupaye in a bank on 11 January of 2012 and was repaid on 6 June 2012 at the rate of 15/2% find her interest and amount

Answers

Answered by Anonymous
7

R=15/2 % p.a

P=2400 rupees

Assuming that it is SI(Simple Interest).

Date of deposition- 11th January 2012

Date of repayment- 6th June 2012

As, 2012 is a leap year, so February has 28 days.

No of days=(31-11) + 28 +31+ 30 + 31 +5

=>20+ 28 + 31 +30 + 31 +5

=> 147  days in all

=>147/366 year. (366 days in 1 leap year)

S.I=P * n * R/100

S.I=2400 *147/366 * 15/2 /100

S.I=24 * 147/366 *15/2

S.I=12 * 147/366 *15

S.I=72.295 rupees.

A=P+S.I

A=2400+72.295

A=2472.295 rupees.

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