Question

Rahana took a wire of CU of length L, area of cross section A and resistance R. She stressed it to four times of its initial length keeping the volume of wire constant. Then she cut it into 8 pieces of equal length. She made four sets by connecting two pieces in parallel. Out of four sets she connected two sets in parallel and remaining two sets in series with a battery of voltage V.

Ans. the following question.

1] New resistance of the wire after stretching is
a) 4R
b) 8R
c) 12R
d) 16R

2] Resistance of each piece of wire is
a) R
b) 2R
c) 3R
d) 4R

3] The equivalent resistance of the circuit is
a) R/2
b) 3R/2
c) 5R/2
d) 7R/2

4] Net current in the circuit is
a) 2V/R
b) 2V/3R
c) 2V/5R
d) 2V/7R​

Answer 1

Answer:

Rahana took a wire of CU of length L, area of cross section A and resistance R. She stressed it to four times of its initial length keeping the volume of wire constant. Then she cut it into 8 pieces of equal length. She made four sets by connecting two pieces in parallel. Out of four sets she connected two sets in parallel and remaining two sets in series with a battery of voltage V.

Ans. the following question.

1] New resistance of the wire after stretching is

a) 4R

b) 8R

c) 12R

d) 16R

2] Resistance of each piece of wire is

a) R

b) 2R

c) 3R

d) 4R

3] The equivalent resistance of the circuit is

a) R/2

b) 3R/2

c) 5R/2

d) 7R/2

4] Net current in the circuit is

a) 2V/R

b) 2V/3R

c) 2V/5R

d) 2V/7R