Rahim removes all the hearts from the cards which is the probability of
1 getting an Ace from the remaining pack
2. Getting a Diamonds
3. Getting a card that is not a heart
4. Getting the ace of heart
Answers
Answer:
1. probability of getting an Ace from the remaining pack = 1/13
2.probability of getting a Diamonds = 1/3
3. probability of getting a card that is not a heart = 1
4. probability of getting ace of heart= 0
Step-by-step explanation:
Deck of playing cards
There are total 52 cards. 4 suites of 13 cards each.
Spade(black), Hearts(red),Diamonds(red) and Clubs (black)
Each suites are ace,king,queen,jack,10,9,8,7,6,5,4,3,2
Kings , queens and jacks are called face card.
Here Rahim removes all the hearts from the cards
There are 13 hearts cards.
Therefore total possibilities are 52 - 13 = 39
Find the probabilities
1. probability of getting an Ace from the remaining pack
there are 3 ace cards in the remaining suites
therefore probability of getting an Ace = 3/39 = 1/13
2.probability of getting a Diamonds
There are 13 diamonds cards
probability of getting a Diamonds = 13/39 = 1/3
3. probability of getting a card that is not a heart
there are no hearts cards.
probability of getting a card that is not a heart = 1
4. probability of getting ace of heart
there are no hearts cards.
probability of getting ace of heart = 0
Answer:
Step-by-step explanation:
Rahim removed all the hearts from deck of cards, so there are only 39 cards left.
1) Since Ace of heart is removed there are only 3 aces left, hence probability of getting an ace would be 3/39 = 1/13.
2)Since all 13 diamond cards are in the deck, probability of getting a diamond would be 13/39 = 1/3.
3.)Since all the heart cards are removed from the deck, always we end up with a non heart card,hence Probability of getting that is not a heart would be 1.
4)Since all the heart cards are removed from the deck, there would be no ace of heart left in the deck, hence Probability of getting the ace of heart would be 0.