rahim scored 32%marks in an examination and failed by 12marks .Mohan scored 42%marks and got 28 more than the minimum pass marks.Find the maximum marks and pass percentage of marks
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Answered by
9
let the maximum mark be a
Rahim's marks = 32a/100
Mohan's marks = 42a/100
According to question
42a/100 -28 = 32a/100 + 12
=> 42a/100 -32a/100 = 40
=> 10a/100 = 40
=> a = 400
Maximum mark = 400
Passing mark = 32 × 400 / 100. +12
= 128 + 12
= 140
Rahim's marks = 32a/100
Mohan's marks = 42a/100
According to question
42a/100 -28 = 32a/100 + 12
=> 42a/100 -32a/100 = 40
=> 10a/100 = 40
=> a = 400
Maximum mark = 400
Passing mark = 32 × 400 / 100. +12
= 128 + 12
= 140
Answered by
1
Answer is 140. Read, Reflect, Recite and Review
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