Math, asked by Jayasurya2O, 1 year ago

Rahim travels 600 km to his home partly by train and partly by car. He takes 8 hrs if he travels 120 km by train and rest by car. He takes 20 min more if he travels 200 km by train and rest by car. Find the speed of the train and the car.

PLEASE SOLVE THIS I WILL MARK AS BRAINLIEST.

Answers

Answered by dewangSINGLA
1

let x=speed of train

let y=speed of car

travel time=distance/speed

..

120/x+480/y=8

200/x+400/y=8+1/3=25/3

..

let u=1/x

let v=1/y

..

120u+480v=8

200u+400v=25/3

..

120u+480v=8

600u+1200v=25

..

600u+2400v=40 (multi. by 5)

600u+1200v=25

subtract

1200v=15

v=15/1200

y=1/v=1200/15=80

..

120u=8-480v=8-(480*15/1200)=8-6=2

u=2/120=1/x

x=120/2=60

..

ans:

speed of train=60 km/hr

speed of car=80 km/hr


dewangSINGLA: please make me a brainlist answer
Answered by botanyliker
0

average speed =600/8=75km/hr

train covers 120km

but,if it will cover200km then

more distance will be 200-120=80km

now speed of train=80÷20/60=240km/hr

now

speed of car=1/average speed -1/speed of train

=1/75-1/240

=1200/11km/hr


Jayasurya2O: Thank you for answering my question but I think it was wrong.
botanyliker: how
Jayasurya2O: Please check the answer given by DewangSINGLA. You will understand how your answer was wrong.
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