Question

Rahul and Teena together can do a piece of work in 18 days. If Teena works alone for last 20 days, then
the work is done altogether in 30 days. In how many days each alone could do the same work? ​

Answer 1

same process only number will change

Step-by-step explanation:

(M+B)24 is Total Work.

=> (M+B)24 = (M+B)20 + (M)6

[Because now total work is completed in 26 days (Man alone does the work for last 6 days, therefore remaining work done by M+B for 20 days).]

By solving above equation:

=> M/B = 2/1 (Efficiency of M and B)

The boy will take to complete the work alone:

=> (M+B)24 = (B)D

=> (2+1)24 = (1)D

=> D = 72

Answer 2

Answer:

mark as branliest

Step-by-step explanation:

D= 72 answer