rahul borrowed rs 830 from mr Lal at 12% p.a. s.i for 3 years. he then added some more money to the borrowed sum and let it to Shobha for the same period at 14% p.a rate of interest,if Rahul gains rs 93.90 in the whole transaction,how much money did he add from his side?
Answers
Answered by
10
Firstly Lal to Rahul
P=830
R=12%
T=3
SI=PRT/100
SI=830*12*3/100
SI=298.8
A=830+298.8=1128.8
Now Rahul to Shobha,
P=830+X
R=14%
T=3
SI=PRT/100
SI=(830+X)*14*3/100
SI=0.42(830+X)
A=830+0.42(830+X)
A.T.Q.
830+0.42(830+X)=1128.8+93.90
830+0.42(830+X)=1222.7
0.42(830+X)=392.7
830+X=935
X=105
Hence he added 105.
P=830
R=12%
T=3
SI=PRT/100
SI=830*12*3/100
SI=298.8
A=830+298.8=1128.8
Now Rahul to Shobha,
P=830+X
R=14%
T=3
SI=PRT/100
SI=(830+X)*14*3/100
SI=0.42(830+X)
A=830+0.42(830+X)
A.T.Q.
830+0.42(830+X)=1128.8+93.90
830+0.42(830+X)=1222.7
0.42(830+X)=392.7
830+X=935
X=105
Hence he added 105.
Answered by
2
Rahul added Rs 105 from has Side
Step-by-step explanation:
Rahul borrowed rs 830 from mr Lal at 12% p.a. s.i for 3 years
P = Rs 830
R = 12 %
T = 3 Years
SI = P * R * T/100
=> SI = 830 * 12 * 3 /100 = 298.8 Rs
Let say Rahul Added M rs
P = Rs 830 + M
R = 14 %
T = 3 Years
SI = P * R * T/100
=> SI = (830 +M) * 14 * 3 /100 = 348.6 + 0.42M Rs
348.6 + 0.42M - 93.90 = 298.8
=> 0.42M = 44.1
=> M = 105
Rahul added Rs 105 from has Side
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