Question

Rahul donate some part of his income to an orphanage every month in a particular month he wishes to donate toys for the children each toy is in the form of a cone mounted on a cylinder of common base radius 7 cm the total height of the toys 25 cm and height of the conical part is 3 cm find the volume of each toy also find the cost of materials used in making one Tai @ Rupees 15 per cm cube what type of nature is shown by Rahul

Answer 1

HELLO DEAR,




GIVE THAT :-


THE RADIUS OF THE CYLINDER =7CM



AND THE TOTAL HEIGHT OF THE TOY IS


= 25CM

AND HEIGHTOF THE CONE IS 3CM =h1

THEREFORE,

THE HEIGHTOF THE CYLINDER IS


=> (25-3) =22cm = h2


NOW THE VOLUME OF THE TOY IS



=>VOLUME OF CONE +

VOLUME CYLINDER =>
$\frac{1}{3} \pi {r}^{2} h_{1} + \pi {r}^{2} h_{2} \\ = >$


NOW PUTTING THE VALUES

WE. GET,
$\pi {r}^{2} ( \frac{1}{3} h_{1} + h_{2}) \\ = > \pi {r}^{2} ( \frac{1}{3} \times 3 + 22) \\ = > \pi {r}^{2} (1 + 22) \\ = > \frac{22}{7} \times {7}^{2} \times 23 \\ = > 22 \times 7 \times 23 \\ = > 154 \times 23 \\ = > 3542c {m}^{3}$



AND ,

THE COST OF THE MATERIALS USED IN

MAKING ONE TAI @ RUPEES 15 per cm³

=>VOLUME OF TOY ×COST OF TOYS



=>.
$= > 3542 \times 15 \\ = > 53130$
AND THE NATURESHOW BY THE RAHUL IS
:- HE IS HAPPY TO DONATES THE TOYS TO

CHILDREN'S

AND
HE ALSO HAPPY IN THE HAPPY OF

CHILDREN'S


I HOPE ITS HELP YOU DEAR
THANKS