Question

Rahul has (x^2+9x+18) sweets. there are (x+3) children. how many sweets are distributed to each?

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

(x+6)

Step-by-step explanation:

Given that,

Rahul has (x^2 +9x +18) sweets.

No. of children = (x+3)

To find the number of sweets distributed.

Let the number of sweets distributed to each children be y.

Therefore, we must have,

=> y(x+3) = (x^2+9x+18)

Further solving, we get,

=> y(x+3) = x^2 + 6x+3x+18

=> y(x+3) = x(x+6)+3(x+6)

=> y(x+3) = (x+6)(x+3)

Comparing coefficient on both sides, we get,

=> y = (x+6)

Hence, required no. of sweets is (x+6).