Rahul owns a rectangular field of length 400m and 200m.His friend ramu owns a square field of length 300m.Find the cost of fencing the two field at 150 per meter.If one tree can be planted in an area of 10sq m.who can plant mm ore trees in his Field?How many more trees can he plant ?
Answers
Answer:
8000
400 into 200 is equal to 80000 and your question is how many trees can be planted in the area of 10 square metre and we have to divide the product of 400 into 200 is equal to 80,000 by 10 so we get the answer 8,000
Answer:
Step-by-step explanation:
In rahul's field ;
(Rectangle)
Length=2(l+b)
= 2×(400+200)
= 2× 600
=1200 m
Cost = length × rate
= 1200×150
= ₹1,80,000
In ramu's field ;
(Square)
Length=4a
=4×300
=1200m
Cost =length×rate
=1200×150
=₹1,80,000
Area of rectangle (rahul): l×b
=200×400
=80000 m sq
No. Of trees planted =80000÷10
=8000 trees
Area of square (ramu):a^2
=300×300
=90000sq m
No. Of trees planted =90000÷10
=9000trees
Thus ramu can plant more trees
He can plant 1000 trees more