Math, asked by Ammochougle, 5 months ago

rahul painted 5/11 part of wall and mihir painted 1/2 of the same wall . how much part of the wall needs to be painted

Answers

Answered by mronaldoaryan2
2

Rahul painted=5/11 part

Mihir painted=1/2 part

total painted part=5/11+1/2

\begin{gathered} \frac{5}{11} + \frac{1}{2} \\ = \frac{10 + 11}{22} \\ = \frac{21}{22} \: part \\ remaining \: part \: to \: be \: painted \\ = 1 - \frac{21}{22} = \frac{22 - 21}{22} = \frac{1}{22} \end{gathered}

11

5

+

2

1

=

22

10+11

=

22

21

part

remainingparttobepainted

=1−

22

21

=

22

22−21

=

22

1

Answered by sumedhdighe
2

Answer:

1/22th wall

Step-by-step explanation:

Total wall painted :

= 5/11 + 1/2

= 10/22 + 11/22

= 21/22th wall is painted

Remaining wall to be painted :

= 1 - 21/22 [1 is whole wall]

= 22/22 - 21/22

= 1/22 th part remaining to be painted

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