The first term of an A. P is -18 and last term is 414. If the common difference is 8 . Find the sum of all terms of this A.P.
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Answer:
sn = 10890
Step-by-step explanation:
a = -18
an = 414
d = 8
n = ?
sn = ?
Now,
an = a + (n-1)d
414 = -18 + (n-1) × 8
414 = -18 + 8n-8
414+18 = 8n-8
432 = 8n-8
432+8 = 8n
440 = 8n
n = 440/8
n = 55
Now,
sn = n/2 [2a + (n-1)d]
or
n/2 [a + an] l is the last term.
Now,
sn = 55/2 [-18 + 414]
sn = 55/2 × 396
sn = 55 × 198
sn = 10890
Hope it helps..........
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