Question

Rahul played well in this season. His current batting average is 51. If he scores 78 runs in today's match, his batting average will become 54. How many matches had he played in this season? Select one: 9 8 10 6

Answer 1

51x+78=54(x+1)

3x=24

x=8

but like if your including the match he just played the answer could be 9.

Answer 2

Answer:

8 matches

Step-by-step explanation:

We are given that Rahul played well in this season. His current batting average is 51.

Let n be the number of matches

$Average = \frac{\text{Sum of all runs}}{\text{Total no. of matches}}$

$51 = \frac{\text{Sum of all runs}}{n}$

$51n =\text{Sum of all runs}$

Now we are given that he scores 78 runs in today's match, his batting average will become 54.

So, Sum of runs = 51n+78

No. of matches = n+1

Now, $54 = \frac{51n+78}{n+1}$

$54n+54 = 51n+78$

$3n= 24$

$n=\frac{24}{3}$

$n=8$

Hence he had played 8 matches.