Math, asked by GunikaAditya, 1 month ago

Rahul, the man who delivers eggs to my home every day, did not turn up one day. So,

when he came the next morning I demanded an explanation from him. He told me the

following story: The previous morning when he just came out of the house carrying a

basketball of eggs on his head to start his daily rounds and stepped on to the street, a car

going on full speed brushed against him and knocked down his basket destroying all the

eggs. The driver, however, a thorough gentleman admitted his responsibility and offered
compensate him for damages. But Rahul could not remember the exact number of eggs
he had, but he estimated the number between 50 and 100. He was also able to tell the
gentleman that if the eggs were counted by 2’s and 3’s at a time, none would be left, but if

counted by 5’s at a time ,3 would remain, and that he sold the eggs 50 paise a piece. The

gentleman made some quick calculations and paid Rahul adequately. How much did the

gentleman pay Rahul

please answer I will mark brainliest​

Answers

Answered by yadavdurjay
4

Answer: Solution:

The simplest way is to find those numbers between 50 and 100, which are multiples of 2 and 3 leaving no remainder. These numbers are 54, 60, 66, 72, 78, 84, 90 and 96. By scrutiny we find that if 78 is divided by 5 it will give 15 plus 3 left over. Therefore 78 is the total number of eggs rahulhad in his basket, before the accident. And therefore he was paid Rs.39 by the gentleman.

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Answered by harshmaurya128
1

Step-by-step explanation:

LCM of 2 and 3 =6.and in between 50 and 100. 78 comes which is when devisible by 5 leaves a remainder 3 so, 78*.50=39 rupees

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