Question

Rain appears to be falling at an angle of 53° with the vertical to a man standing on the ground

Answer 1

Step-by-step explanation:

Given Rain appears to be falling at an angle of 53° with the vertical to a man standing on the ground. When he starts running at 10 km/hr, rain again appears to be falling at 53 degree with the vertical. Find the speed of rain with respect to ground.

• So it appears raining at an angle of 53 degree and there is a man standing vertical to the ground that is he is at rest.
• Now the man starts running at a speed of 10 km/hr, and it appears to rain at an angle of 53 degree.
• So velocity of rain with respect to man is 53 degree with vertical.
• So vector of velocity of man w.r.t to rain = velocity of rain vector – velocity of man vector.
• We need to find velocity of rain.
• So we get Vr sin 53 and Vr cos 53
•       So sin 53 = 4/5
•    So net component will be   10 – Vr x 4/5
•              Now Vr cos 53 will be
•                       Vr x 3/5
• So resultant vector will be 37 degree.
•         So tan 37 = Vr x 3/5 / 10 – Vr x 4/5
•             ¾ = 3Vr / 5(50 – 4Vr / 5)
•              4 Vr = 50 – 4Vr
•                 8Vr = 50
•                    Or Vr = 50 / 8
•                     Vr = 25 / 4 km/hr
• So velocity of rain will be 25/4 km/hr

Reference link will be

https://brainly.in/question/3048365

Answer 2

Answer:  25/4 km/hr

Step-by-step explanation:

Given : Rain appears to be falling at an angle of 53° with the vertical to a man standing on the ground.

When he starts running at 10 km/hr, rain again appears to be falling at 53 degree with the vertical.

To Find : The speed of rain with respect to ground.

Solution :

It appears raining at an angle of 53° and there is a man standing vertical to the ground that is he is at rest.

Now the man starts running at a speed of 10 km/hr, and it appears to rain at an angle of 53° .

So velocity of rain with respect to man is 53 degree with vertical.

So vector of velocity of man w.r.t to rain = velocity of rain vector – velocity of man vector.

∵ We need to find velocity of rain.

So we get V sin 53 and V cos 53

So sin 53 = 4/5

So net component will be :  10 – V * 4/5

Now V cos 53 will be

V * 3/5

So resultant vector will be 37° .

So tan 37 = V * 3/5 / 10 – V * 4/5

¾ = 3V / 5(50 – 4V / 5)

4 V = 50 – 4V

8V = 50

Or V = 50 / 8

V = 25 / 4 km/hr

So velocity of rain will be 25/4 km/hr

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