Question

Rain water falls on a flat rectangular surface of length 6 m and breadth 4m is transferred into a cylindrical vessel of internal radius 20 CM. What will be the height of water in the cylindrical vessel of the rainfall in 1 CM Give ur answer to the nearest whole number.( Take
$\pi = 3.14)$

Answer 1

Length of rectangular surface

${ =\: 6\: m}$

${ =\: 600 \:cm}$

Breadth ${ =\: 4\: m}$ ${ =\: 400 \:cm}$

Height $= 1 \:cm$

Radius of cylindrical vessel (r) $= 20 \:cm$

Let the height of cylindrical vessel be $h\:cm$

Vol of rectangular surface = Vol of cylindrical vessel

L × B × H = $\pi \: r ^{2} h$

$600 \times 400 \times 1 = \frac{22}{7} \times (20) ^{2} \times h$

$24000 = \frac{22}{7} \times 400 \times h$

$\frac{24000}{400} = \frac{22}{7} \times h$

$60 = \frac{22}{7} \times h$

$60 \times 7 = 22 \times h$

$420 = 22 \times h$

$\frac{420}{22} = h$

$190.90 = h$

$\bold{Therefore,}$

Height of the cylindrical vessel is $190.90\:cm.$

Answer 2

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