raindrops are falling vertically with a speed of 5m/s w.r.t ground. To a boy running in rain, rain drops are falling with 10m/s.The speed of the boy and the angle with vertically with which rain is being appeared to the boy will be
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v² + 5² = 10²
v = 5√3 m/sec. = speed of the boy.
The velocity of rain and the boy are perpendicular vectors.
Angle with the horizontal = Ф
Tan Ф = 5 / 5√3 = 1/√3
The boy has to look at 17.32 degrees upwards.
v = 5√3 m/sec. = speed of the boy.
The velocity of rain and the boy are perpendicular vectors.
Angle with the horizontal = Ф
Tan Ф = 5 / 5√3 = 1/√3
The boy has to look at 17.32 degrees upwards.
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