Raindrops are falling with velocity 10root2 m/a making an angle 45 degrees with the vertical the drops appear to be falling vertically to a person running with constant velocity the velocity of raindrops change such that the rain now appears to be falling vertically with root3 times the velocity it appeared earlier to the same person running with same velocity
1. After the velocity of rain drops change the magnitude of velocity of raindrops with respect to ground is
2. The angle between the initial and final velocity of raindrops with respect to ground
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Step-by-step explanation:
Given Raindrops are falling with velocity 10 root 2 m/s making an angle 45 degrees with the vertical the drops appear to be falling vertically to a person running with constant velocity the velocity of raindrops change such that the rain now appears to be falling vertically with root 3 times the velocity it appeared earlier to the same person running with same velocity.
1. After the velocity of rain drops change the magnitude of velocity of raindrops with respect to ground is
2. The angle between the initial and final velocity of raindrops with respect to ground
- Given rain drops are falling with velocity 10 √2 m/s in the frame of earth making an angle 45 degree.
- Now velocity of rain with respect to earth will be – 19 i – 10 j and these are the components.
- So velocity of person with respect to earth = V i
- Also velocity of person with respect to rain will be (V + 10) i + 10 j
- Given the drops appear to be falling vertically to a person when it runs with some constant velocity. The drops are falling vertically to the person and so the horizontal component should be 0.
- Therefore v + 10 = 0
- Or v = - 10 m/s
- Or velocity = 10 m/s
- Now V resultant = √3 V
- = 10 √3
- So we have tan theta = 10 / 10 √3
- Or theta = tan ^-1 1/√3
- = 30 degree
- Now angle between initial and final velocity of rain drops = 45 – 30 = 15 degree
Reference link will be
https://brainly.in/question/12244691
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