Rainu is 8 years younger than her brother shanu. If the sum of their ages is 42 years , find their ages ?
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Let Rainu' s age = x
Shanu' s age = x+8
Sum of their ages
x+x+8 = 42
2 x+8 = 42
2 x = 42 - 8
2 x = 34
x = 34/2
x = 17
Rainu' s age = x = 17
Shanu' s age = x + 8 = 17+8 = 25
Shanu' s age = x+8
Sum of their ages
x+x+8 = 42
2 x+8 = 42
2 x = 42 - 8
2 x = 34
x = 34/2
x = 17
Rainu' s age = x = 17
Shanu' s age = x + 8 = 17+8 = 25
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