the nth term of a sequence is 8-5n .show that the sequence ia an AP
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8 -5n
putting n=1
8-5×1
=8-5=3 again
putting n=2
8-5×2
8-10
-2
again
putting n=3
8-5×3
8-15=-7
hence the common difference is -5
this sequence is in a.p
putting n=1
8-5×1
=8-5=3 again
putting n=2
8-5×2
8-10
-2
again
putting n=3
8-5×3
8-15=-7
hence the common difference is -5
this sequence is in a.p
Leo444:
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