Raj is 6 years older than Diya. One half of Raj's age exceeds one third of Diya's age by 4 years. Find their ages
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Hi ,
Let Diya's age = x years
Raj's age = ( x + 6 ) years
According to the given problem,
One half of Raj's age exceeds one
third of Diya's age by 4 years
1/2 ( x +6 ) - x /3 = 4
(x + 6 )/2 - x /3 = 4
3( x + 6) -2x = 24
3x + 18 -2x = 24
x = 24 - 18
x = 6
Therefore ,
Diya's age = x = 6 years
Raj's age = ( x + 6 ) = ( 6 + 6 ) = 12 yrs
I hope this helps you.
****
Let Diya's age = x years
Raj's age = ( x + 6 ) years
According to the given problem,
One half of Raj's age exceeds one
third of Diya's age by 4 years
1/2 ( x +6 ) - x /3 = 4
(x + 6 )/2 - x /3 = 4
3( x + 6) -2x = 24
3x + 18 -2x = 24
x = 24 - 18
x = 6
Therefore ,
Diya's age = x = 6 years
Raj's age = ( x + 6 ) = ( 6 + 6 ) = 12 yrs
I hope this helps you.
****
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