Raj is having a triangular open space in his plot.He divided the land into two parts by drawing the boundary PQ,where PQ II BC ,P is the midpoint of side AB other measures are given as height of triangle is 12cm,AP=7cm ,BC =10cm,AC=11cm Find
Area of triangle ABC is
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Given : A triangular open space in his plot.
He divided the land into two parts by drawing the boundary PQ, where PQ || BC.
P is the mid point of side AB
Height of triangle is 12 cm
AP = 7 cm, BC = 10 cm AC = 11 cm.
To Find :
Area of ∆ ABC
Solution:
Height of triangle is 12 cm
Base BC = 10 cm
Area of ΔABC = (1/2) * base * height
= (1/2) * BC * height
= (1/2) * 10 * 12
= 60 cm²
Area of ΔABC = 60 cm²
2}Length of side PQ = BC/2 = 10/2 = 5 cm
3}Length of AQ is = AQ = AC/2 = 11/2 = 5.5 cm
4}Length of PB = AP = 7 cm
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