Raj’s age is 5 more than three times Suraj’s age. Find the rule for
finding Raj’s age in terms of age of suraj.
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Answered by
3
Answer:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
(4x + 8) = 5 (x + 8)
2
8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio = (4x + 16) = 48 = 2.
(x + 16) 24
Explanation:
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Answered by
0
Suppose Suraj x.
Raj= 5+3x
So Raj’s age 5+ 3x
Raj= 5+3x
So Raj’s age 5+ 3x
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