raj takes a certain number of rotis during lunch but always wastes half a roti.riya takes half the number of rotis as raj and always finishes her share.after 20 days if the number of rotis that were consumed during lunch by them together is 110 (excluding the wasted rotis)then find the number of rotis per meal that raj and riya take. how many rotis were wasted in 20 days
Answers
Answered by
3
Let the number of rotis taken by Raj = x
Let the number of rotis eaten by Raj = x - 1/2
Let the number of rotis eaten by Riya = x/2
Given: Total number of rotis eaten in 20 days = 110
i.e., 20 (x - 1/2) + 20 (x/2) = 110
20x -10 + 10x =110 (20x - 20/2 + 20x/2)
30x - 10 = 110
30x = 110 + 10
30x = 120
x = 120/30
x = 4
Therefore, the number of rotis
taken by Raj = 4
eaten by Raj = 4 - 1/2 = 3 1/2 (3.5)
eaten by Riya = 4/2 = 2
No. of rotis wasted in 20 days = 20 (1/2) =10
Let the number of rotis eaten by Raj = x - 1/2
Let the number of rotis eaten by Riya = x/2
Given: Total number of rotis eaten in 20 days = 110
i.e., 20 (x - 1/2) + 20 (x/2) = 110
20x -10 + 10x =110 (20x - 20/2 + 20x/2)
30x - 10 = 110
30x = 110 + 10
30x = 120
x = 120/30
x = 4
Therefore, the number of rotis
taken by Raj = 4
eaten by Raj = 4 - 1/2 = 3 1/2 (3.5)
eaten by Riya = 4/2 = 2
No. of rotis wasted in 20 days = 20 (1/2) =10
Answered by
0
Let Raj takes x number of rotis.
Raj consumes x-0.5 rotis
Riya takes half of x = x/2 rotis
In 20 days they consume (x-0.5 + x/2)*20=110
⇒ 3x-1=11
⇒ x=4
Raj takes 4 rotis and Riya takes 2 rotis
No of rotis wasted is 0.5*20=10 rotis
Raj consumes x-0.5 rotis
Riya takes half of x = x/2 rotis
In 20 days they consume (x-0.5 + x/2)*20=110
⇒ 3x-1=11
⇒ x=4
Raj takes 4 rotis and Riya takes 2 rotis
No of rotis wasted is 0.5*20=10 rotis
Similar questions
Math,
8 months ago
Math,
8 months ago
Political Science,
8 months ago
English,
1 year ago
English,
1 year ago
Social Sciences,
1 year ago
Environmental Sciences,
1 year ago