Chemistry, asked by lawerencedsouza, 1 year ago

Raj took 5 moles of carbon atoms in a container and Krish also took 5 moles of sodium atoms in another container of same weight.
a. Whose container is heavier?
b. Whose container has more number of atoms?

Answers

Answered by saianand
2
1.) 1 mole of carbon atoms = 12 gm
So, 5 moles of C-atoms = 12x 5  = 60 gm
Similarly, 
1 mole of Na-atoms = 23 gm
5 moles of Na-atoms = 23 x 5 = 115 gm
So, Krrish's container with sodium atoms is heavier.
2). Since, 1 mole = Avogadro no. of atoms(for monoatomic elements)
And, both C and Na are found monoatomic so, no. of moles will be equal in each container.

lawerencedsouza: Hi
lawerencedsouza: Thanks
Answered by cuty01
6

Explanation:

</p><p>\huge\underline{\underline{\sf{\purple{Required\:answer:}}}}

Number of moles of carbon in Raj's container = 5 mol

Weight of 1 mol of carbon atoms = 12

Now , Weight of 5 moles of carbon atoms = 12 × 5 = 60 g

Number of moles of sodium in krish's container = 5 moles

Weight of 1 mol of Sodium = 23 g

Now , Weight of 5 moles of sodium = 23 × 5 = 115 g

By observing the above calculations . We can say that Krish's container is heavier compared to Raunak's container.

And Now ,Coming to the number of atoms ;

Product of number of moles of substance and avogadro number (6.023×10²³) gives the number of atoms in that substance.

The number of moles of both taken atoms is same. So , Number of atoms will also be same.

Hence ,

Krish's container is heavier compared to Raj's container and Number of atoms present in both containers is same.

Similar questions