Question

raja
$(m+n)x+(m-n)y=m^2-2mn-n^2.(m+n)(x+y) = m^2+n ^2$
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Answer 1

Answer:

Step-by-step explanation:

m(x+y)+n(x-y)-(m²+mn+n²)=0

n(x+y)+m(x-y)-(m²-mn+n²)=0

( m +n ) x + (m-n)y - (m²+mn+n²) = 0

( m +n ) x - (m-n)y - (m²-mn+n²) = 0

2( m +n ) x - 2( m² + n²) = 0   ,  2(m-n)y  - 2mn = 0

x = ( m² + n² ) ÷ (m+n) ,   y  =  mn ÷ (m-n)