Question

rajat covered a straight line distance between two states in three parts. he coverd the 1/4 th the distance of speed 20 km/hr. he coverd the 1/6 th of the remaining distance at the speed of 35 km/hr and the rest of distance at 40km/hr. what will be avaerage speed forthe whole journey

Answer 1

Let the distance travelled be=240 Kms.

1/4 th distance=1/4 x240= 60 Kms. Speed of travel=20Km/ h. Time of travel=60/20= 3 hrs.

1)6 the distance=1/6 x240=40. Speed of travel=35Km/h. Time of travel=40/35=1.14285 h.

Rest of distance=1-(1/4+1/6)=7/12. So 7/12 the distance=140 Km. Time of travel=140/40= 3.5 h.

Average Speed=Total dis /Total Time. = 240/(3+1.14285+3.5)= 240/7.64285= 31.40 Km/h

Answer 2

The average speed be for the entire trip is 32 km per hr when Rajat travelled three segments of a straight line between two states.

Given that,

Rajat travelled three segments of a straight line between two states. He travelled at a speed of 20 km per hr for the $\frac{1}{4}$ distance. He travelled the remaining $\frac{1}{6}$ of the trip at a speed of 35 km per hr and the remaining distance at a speed of 40 km per hr.

We have to find what will the average speed be for the entire trip.

We know that,

$\frac{1}{4}$th the distance of speed 20 km per hr.

$\frac{1}{6}$th the distance of speed 35 km per hr.

Remaining distance is

$1- (\frac{1}{6}+\frac{1}{4})$ distance of speed 40 km per hr.

Now,

Average speed = $\frac{20+35+40}{3}$ = $\frac{95}{3}$ = 32 km per hr.

Therefore, The average speed be for the entire trip is 32 km per hr.

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