Math, asked by kangappan1663, 10 months ago

Rajesh buys 12 computers and 12 printers if the cost of one computer and one printer is 56233 and 7867 respectively find the total cost incurred by rohan. Use distributive property

Answers

Answered by raj3294
14

Answer:

Step-by-step explanation:

COST OF ONE COMPUTER = RS.56233

COST OF 12 COMPUTERS = 56233*12

                                             = RS.6,74,796.

COST OF ONE PRINTER = RS. 7867.

COST IF 12 PRINTERS = 7867*12

                                     = RS. 94,404.

TOTAL COST = 6,74,796+94,404

                       = RS.7,69,200.

THEREFORE THE TOTAL COST IS RS.7,69,200.

HOPE THIS HELPS.

Answered by shailaj6a
1

Answer:

776400

Step-by-step explanation:

cost of 1 computer=56233

cost of 1 printer=7867

total cost for 6 computers and 6 printers=12^56833+12^7867

                                                                     12^(56833+7867)

                                                                     12^64700

                                                                      776400

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