Question

rajesh solved 80% of questions in an exam correctly. if out of 41 questions solved by rajesh 37 questions are correct and of the remaining questions out of 8 questions 5 questions have been solved by rajesh correctly then find the total number of questions asked in the examination

Answer 1

Let us suppose that there are y questions 
⇒No. of questions answered correctly=5y/41
⇒No. of remaining question=8y
                       A.T.Q
37 + 5y/41 + 8y = 80% = 4/5 
⇒ 185 + 25y = 164 + 32y 
⇒ 7y = 21 
⇒ y = 3 
∴ Total no. of questions = 41 + 8 x 3 = 65. 

Answer 2

let the no. of questions be x

no. of correct answers= 80% of x 4/5n

ATC

37 + (n-4) × 5/8= 4n/5 or 37+ 5n/8 - 205/8= 4n/5

or 37-205/8=4n/5-5n/8 or 296-205/8= 32n-25n/40

or 91/8=7n/40= n= 91×40/8×7=65