Rajiv can do a piece of work in 10 days , venky in 12 days and ravi in 15 days. they all start the work together, but rajiv leaves after 2 days and venky leaves 3 days before the work is completed. in how many days is the work completed ?
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total work=lcm of 10,12,15=180
rajiv 1 day work=180/10=18
venky 1 day work=180/12=15
ravi 1 day work=180/15=12
all three 1 day work=18+15+12=4let x be the days to completion of work
rajiv working day=2
venky working days=x-3
ravi working days=x
now,18×2+15(x-3)+12x=180
36+15x-45+12x=180
27x-9=180
x=189/27=7 days
rajiv 1 day work=180/10=18
venky 1 day work=180/12=15
ravi 1 day work=180/15=12
all three 1 day work=18+15+12=4let x be the days to completion of work
rajiv working day=2
venky working days=x-3
ravi working days=x
now,18×2+15(x-3)+12x=180
36+15x-45+12x=180
27x-9=180
x=189/27=7 days
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