Question

Raju and Shyam are friends. Raju has a square field of side 50 m and Shyam has a
rectangular field of length 60 m and breadth 40 m. Compare the perimeters and
areas of the two fields.​

Answer 1

Step-by-step explanation:

I get the answer.......

Answer 2

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• SOLUTION :

→ GIVEN , SIDE OF THE SQUARE OF RAJU = 50m

therefore , Perimeter = 4s

= 4 (50) m

= 200 m

→ ALSO GIVEN , BREADTH OF RECTANGLE= 40m

LENGTH OF RECTANGLE = 60 m

therefore, perimeter = 2(l+b)

= 2 (60 + 40)

= 2(100)

= 200m

On comparing both the parameters we find that the perimeter of square is equal to perimeter of rectangle .

HOPE IT HELPS ❣️｡.ﾟ+ ⟵(｡･ω･)