Math, asked by SakshamNigam12, 1 year ago

Water flows through a cylindrical pipe of internal diameter 7 cm at 5 m per sec.
Calculate
(i) the volume in litres of water discharged by the pipe in one minute.
(ii) the time in minutes, the pipe would take to fill an empty rectangular tank of size
4 m x 3 m x 2.31 m.​

Answers

Answered by swastika07642
18

Answer:

Here is ur answer dear.....

In one sec. length of water flow in pipe = 5 m

radius = 7/2 = 3.5 cm = 0.0035 m

volume of water flow per sec = π r² h = π(0.0035)² ×5

                                               =192.5× 10^(-6) m³

volume of water discharged per min = 192.5× 10^(-6) m³×60

                                                                = 11.55×10^(-3) m³

                                                                = 0.01155 m³

                                                                =11.55 Liter

volume of tank = 4×3×2.31 = 27.72 m³

∵1m³ = 1000 Liter 

volume of tank = 27720 Liter

time to fill the tank = 27720/11.55 = 2400 minutes

                                                          = 2400/60 = 40 hours

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Answered by Siddharta7
7

Step-by-step explanation:

(i)

In one sec. length of water flow in pipe = 5 m

radius = 7/2 = 3.5 cm = 0.0035 m

volume of water flow per sec = π r² h = π(0.0035)² ×5

                                              =192.5× 10^(-6) m³

volume of water discharged per min :

= 192.5× 10^(-6) m³×60

= 11.55×10^(-3)

= 0.01155

=11.55 Liter

(ii)

volume of tank = 4 * 3 * 2.31

= 27.72 m³

= 27720 Liter

time to fill the tank = 27720/11.55

= 2400 minutes

= 2400/60

= 40 hours

Hope it helps!

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