Water flows through a cylindrical pipe of internal diameter 7 cm at 5 m per sec.
Calculate
(i) the volume in litres of water discharged by the pipe in one minute.
(ii) the time in minutes, the pipe would take to fill an empty rectangular tank of size
4 m x 3 m x 2.31 m.
Answers
Answered by
18
Answer:
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In one sec. length of water flow in pipe = 5 m
radius = 7/2 = 3.5 cm = 0.0035 m
volume of water flow per sec = π r² h = π(0.0035)² ×5
=192.5× 10^(-6) m³
volume of water discharged per min = 192.5× 10^(-6) m³×60
= 11.55×10^(-3) m³
= 0.01155 m³
=11.55 Liter
volume of tank = 4×3×2.31 = 27.72 m³
∵1m³ = 1000 Liter
volume of tank = 27720 Liter
time to fill the tank = 27720/11.55 = 2400 minutes
= 2400/60 = 40 hours
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Answered by
7
Step-by-step explanation:
(i)
In one sec. length of water flow in pipe = 5 m
radius = 7/2 = 3.5 cm = 0.0035 m
volume of water flow per sec = π r² h = π(0.0035)² ×5
=192.5× 10^(-6) m³
volume of water discharged per min :
= 192.5× 10^(-6) m³×60
= 11.55×10^(-3)
= 0.01155
=11.55 Liter
(ii)
volume of tank = 4 * 3 * 2.31
= 27.72 m³
= 27720 Liter
time to fill the tank = 27720/11.55
= 2400 minutes
= 2400/60
= 40 hours
Hope it helps!
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