Question

Raju gave 2 /5 part of money to dev and 3 /10 part to salami. Now he has only 180 rs. How much rs raju had at beginning​

Answer 1

Step-by-step explanation:

$let \: raju \: had \: rs \: x \: in \: beginning \\ therefore \\ \frac{2}{5} x + \frac{3}{10} x + 180 = x \\ \frac{4x + 3x}{10} + 180 = x \\ 7x + 1800 = 10x \\ 1800 = 3x \\ x = 600 \\ therefore \: raju \: had \: 600 \: rupees \: initially$

Answer 2

Answer: Rs. 600

Step-by-step explanation:

Money in hand = x

Given to dev = 2/5 of x = 2x/5

Given to salami = 3/10 of x = 3x/10

Remaining = Rs. 180

How much Raju had at the beginning?

x - ( 2x/5 + 3x/10 ) = 180

x - ( 2x*2/5*2 + 3x/10 ) = 180

x - ( 4x/10 + 3x/10 ) = 180

x - 7x/10 = 180

x*10/1*10 -7x/10 = 180

10x-7x/10 = 180

3x/10 = 180

3x = 180*10

3x = 1800

x = 1800/3

x = 600