Question

Raju is 19 years younger than meena after 5 years their age will be 2:3 . Find their present age

Answer 1

Answer :Raju is 5 years and Meena is 10 years old
Step by step explanation
Let age of raju = x
Meena's age=x+5
After 5 years :
Raju =x+5
Meena =x+5 +5 =x+10
(x+5)/(x+10)=2/3
3(x+5)=2(x+10)
=> 3x+15=2x+20
3x-2x=20-15
x=5
So, Raju 's age is 5
Meena's age is 10
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Answer 2

Ⓖⓘⓥⓔⓝ :-

Raju is 19 years younger than his cousin.

ratios of their ages after 5 years = 2:3

Ⓕⓘⓝⓓ :-

THEIR PRESENT AGES ?

Ⓢⓞⓛⓤⓣⓘⓞⓝ  :-

Let age of cousin be x years

$\therefore$ Age of Raju = x-19 years

After 5 years

Age of cousin = x+5 years

Age of Raju = x - 19 + 5 = x - 14 years

ACCORDING TO QUESTION

$\frac{x - 14}{x + 5} = \frac{2}{3}$

$= 3 \times ( x - 14) = 2( x+ 5)$

$= > 3x - 42 = 2x + 10$

$collect \: like \: terms$

$= > 3x - 2x = 10 + 42$

$x = 52$

So, Present age of:

cousin = x = 52 years

Raju = x -19 = 52 - 19 = 33 years

$so, \: cousin \: present \: age \underline{ \boxed{52 \: years}}$

$and \: Raju\: present \: age \underline{ \boxed{33 \: years}}$