Question

Raju is 40 years old and shurbhi is 20 years old.how many years ago was raju three times as old as shurbhi​

Answer 1

Answer:

10 years ago, Raju was 3 times that the age of Surbhi.

Step-by-step explanation:

Solution :

Raju = 40 years

Surbhi = 20 years

Let the years that to be subtracted be y

• Raj = 40 - y
• Surbhi = 20 - y

★ According to the question,

Raj was 3 times Surbhi's age -

⇒ (40 - y) = 3(20 - y)

⇒ 40 - y = 60 - 3y

⇒ -y + 3y = 60 - 40

⇒ 2y = 20

⇒ y = 20/2

⇒ y = 10

Therefore, 10 years ago, Raju was 3 times that the age of Surbhi.

$\rule{300}{1.5}$

★ Verification:

• Raju 10 years back = 40 - 10 = 30
• Surbhi 10 years back = 20 - 10 = 10

As the question says, Raju was 3 times the age of Surbhi,

⇒ 10 × 3 = 30

Hence proved, that Raju was thrice the age of Surbhi 10 years ago.

Answer 2

solution:-

Let Sharadha's age be x and Smita's age be y

x=40,y=20

let the number of years ago when Sharadha was three times as old as Smita be n.

↠(x-n)=3(y-n)

↠40-n=3(20-n)

↠40-n=60-3n

↠2n=20

↠n=10

Thus,10 years ago Sharadha was three times as old as Smita.