Question

Raju wants to paint a cuboidal box which is 20 cm in length , 15 cm in breadth and 6 cm in depth. Find the area to be painted if the box is open at the top.​

Answer 1

ɢɪᴠᴇɴ :-

• Length (l) = 20 cm
• Breadth (b) = 15 cm
• Height (h) = 6 cm

ᴛᴏ ғɪɴᴅ :-

• Area of Box open at the top

sᴏʟᴜᴛɪᴏɴ :-

We know that,

• Area of Cuboid(Box) = 2(lb + lh + bh)

➮ 2(lb + lh + bh)

➮ 2(20 × 15 + 20 × 6 + 15 × 6)

➮ 2(300 + 120 + 90)

➮ 2(510)

➮ 1020 cm²

Now,

Required area of Box = Area of box - Area of Top

➮ Required area = 1020 - (l × b)

➮ 1020 - (20 × 15)

➮ 1020 - 300

➮ 720 cm²

Hence,

• Area of Box to be painted is 720 cm²

Answer 2

$\huge\underline\star\pink{given:}$

1. length=20cm
2. breadth=15cm
3. height=6cm

$\huge\underline\star\pink{to find}$

• area to be painted of the box at the top

$\huge\underline\star\pink{solution}$

A. T. Q

• area of cuboid box=2(lb+lh+bh).

2(lb+lh+bh)

2(20*15+20*6+15*6)

2(300+120+90)

2(510)

1020 cm^2

$\huge\underline\star\pink{NOW}$

• required area of box= area of box-area of top

A. T. Q

1020-(l*b)

1020-(20*15)

1020-300

720cm^2

HENCE AREA OF BOX TO BE PAINTED IS 720CM^2