Question

Ram and Rahim are good friends what is the probability that both will have different birthdays and The same birthday ignoring a leap year
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Answer 1

Answer:

$\huge \sf \underline{answer}$

Step-by-step explanation:

$\rm{p(both \: have \: different \: birthdays)}$

$\rm{p(both \:will \: not \: have \: same \: birthday)}$

$= \: 1- \frac{1}{365}$

$= \: \frac{365 - 1}{365}$

$= \: \frac{364}{365}$

$\bf{ \huge{ \boxed{\tt{ { \frac{364}{365 \: }}}}}}$

Answer 2

The probability that both have different birthday is $\frac{364}{365}$ and have same birthday  is $\frac{1}{365}$

Step-by-step explanation:

number of days in an year = 365

number of days when same birthday is possible = 1

then

probability = $\frac{\text{number of outcome }}{\text{total outcomes}}$

probability (both have same birthday ) =$\frac{1}{365}$

and

probability (both have different  birthday ) = 1- probability (both have same birthday )

probability (both have different  birthday ) = $1-\frac{1}{365}$

$= \frac{365-1}{365} \\\\=\frac{364}{365}$

hence ,The probability that both have different birthday is $\frac{364}{365}$ and have same birthday  is $\frac{1}{365}$

#Learn more:

What is probablity? define of probablity?​

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