Ram and Shakil run a race of 2000 meters. First, Ram gives Shakil a start of 200 meters and beats him by one minute. If, Ram gives Shakil a start of 6 minutes Ram is beaten by 1000 meters. Find the time in minutes in which Ram and Shakil can run the races separately.
Answers
Given : Ram and Shakil run a race of 2000m
First Ram gives Shakil a start of 200 meters and beats him by 1 minute.
If Rakm gives Shakil a start of 6 minutes Ram is beaten by 1 km.
To Find : the time in minutes in which Ram and Shakil can run the races separately.
Solution:
Ram and Shakil run a race of 2000 m
Ram gives Shakil a start of 200 meters and beats him by 1 minute.
=> Time taken by Ram = T mins
Then time taken by Shakil for 2000 - 200 = 1800 m = T + 1 Mins
Speed of ram = 2000/T
Speed of Shakil = 1800/(T + 1)
Ram gives Shakil a start of 6 minutes Rakesh is beaten by 1 km
Time taken by ram to complete = 2000 - 1000 = 1000 m
= 1000/(2000/T)
= T/2 mins
Time taken by saket to complete race = T/2 + 6 mins
{1800/(T + 1)} { T/2 + 6} = 2000
=> 18( T + 12) = 40(T + 1)
=>18T + 216 = 40T +40
=> 22T = 176
=> T = 8
time in minutes in which Ram races = 8 Min
Speed of Shakil= 1800/(T + 1) = 1800/(8 + 1) = 200 m/min
=> Time taken by Shakil = 2000/200 = 10 min
Ram finish in 8 Mins
Shakil finished in 10 mins
Learn More:
The graph shows the results of a race between Peter and Stuart ...
brainly.in/question/6001664
Miguel and his brother Ario are both standing 3 meters from one ...
brainly.in/question/11007310
Answer:
8 min
Step-by-step explanation:
LET r be velocity of ram and s be the velocity of Shakil
then
(2000/r) = (1800/s)-60 (1)
second case
distance Shakil travel in 6 min=360s
again equating time for both
1000/r=(2000-360s)/s (2)
solving (1) &(2) we get s=20/6
putting value in first we get time =480sec=8min