Question

Ram and Shyam are two friends. Find the probability that their birth days fall on the same day

and also find the probability that their birthday falls on different days. Consider the year 2005.

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Answer 1

No. of days in a year = 365 Since there are two birthdays(Ram and shayam) in a year,

n(S) = 365 x 365 -----------(1)equation

b) Let E be the event that Ram and Shayam have different birth days. But of 365 days Ram can have birthday on any day and hence Shayam can have birthday on (365 - 1) i.e. 364 days.

∴ n(E) = 365 × 364

Now, P(E) = n(E) / n(S) = (365x364) / (365x365) = 364 / 365.

a) Let F be the event that both of them have their birth days on same day. E and F are complementary events. ∴ P(F) = 1 - P(E) Using value of P(A) from (i),

P(F) = 1 – 364 / 365 = 1 /365.

Hope it helps u.

Answer 2

Answer:

raam and hari are tu friend