Math, asked by Ayush51001, 1 year ago

Ram and shyam run a race of 2000 m. first, ram gives shyam a start of 200 m and beats him by30 s. next, ram gives shyam a start of 3 min and is beaten by 1000 metres. find the time inminutes in which ram and shyam can run the race separately.

Answers

Answered by Answers4u
59

Let us denote the running speed of Ram be "A" and Shyam be "B"

In first scenario,

When Ram gives Shyam a start of 200 m and beats him by 30 seconds.

1800/B – 2000/A = 30

In second scenario,

When Ram gives Shyam a start of 3 min i.e. 180seconds and is beaten by 1000 metres

2000/B – 1000/A = 180

Solving the two equation, the values of A and B are:

A= 25/3 m/s

B = 20/3 m/s

Time taken = Distance /Speed

Time taken by Ram to run the ground= 2000*3*/25 = 240 seconds= 4 min

Time taken by Shyam to run the ground = 2000*3/20 = 300 seconds = 5 min

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