Question

Ram and shyam run a race of 2000 m. first, ram gives shyam a start of 200 m and beats him by30 s. next, ram gives shyam a start of 3 min and is beaten by 1000 metres. find the time inminutes in which ram and shyam can run the race separately.

Answer 1

Let us denote the running speed of Ram be "A" and Shyam be "B"

In first scenario,

When Ram gives Shyam a start of 200 m and beats him by 30 seconds.

1800/B – 2000/A = 30

In second scenario,

When Ram gives Shyam a start of 3 min i.e. 180seconds and is beaten by 1000 metres

2000/B – 1000/A = 180

Solving the two equation, the values of A and B are:

A= 25/3 m/s

B = 20/3 m/s

Time taken = Distance /Speed

Time taken by Ram to run the ground= 2000*3*/25 = 240 seconds= 4 min

Time taken by Shyam to run the ground = 2000*3/20 = 300 seconds = 5 min