Math, asked by vanshikashastri7, 10 days ago

Ram bought 40 pens and 50 pencils at the cost of rs 350 and 30 pens and 40 pencils at the cost of rs 270 the cost of one pen and three pencils is

Answers

Answered by tanaybankar1
4

Answer:

Cost of 1 Pen =x=5

Cost of 1 Pencil=y=3

Cost of 1 pen and 3 pencils=14

Step-by-step explanation:

Let cost of 1 pen = x

therefore cost of 40 pens =40x

cost of 30 pens = 30x

Let the cost of 1 pencil=y

therefore, the cost of 50 pencils=50y

cost of 40 pencils =40y

from condition 1, 40x+50y=350

from condition 2, 30x+40y=270

solve equations simultaneously,

x=5,y=3

{

Solving equations:

40x+50y=350

40x=350-50y

x=(350-50y)/40

put the value of x in equation 2 and get the value of y

then put the value of y in x=(350-50y)/40 and get x

}

Finally, we have to find x+3y=?

so put x=5 and y=3

5+3(3)=14

Answered by amitnrw
1

Given: Ram bought 40 pens and 50 pencils at the cost of rs 350

and 30 pens and 40 pencils at the cost of rs 270

To Find :  the cost of one pen and three pencils  

Solution:

cost of one pen  = Rs x

cost of one pencil  = Rs y

40 pens and 50 pencils cost of rs 350

=> 40x + 50y = 350

=> 4x + 5y  = 35   Eq1

30 pens and 40 pencils  cost of rs 270

=> 30x + 40y = 270

=> 3x + 4y =  27   Eq2

4 * Eq1  - 5 * Eq2

=> x = 5

4x + 5y  = 35

=> 20 + 5y  = 35

=> y = 3

cost of one pen and three pencils is = x + 3y

= 5 + 3(3)

= 14  Rs

cost of one pen and three pencils is  14  Rs

Learn More:

represent the cost of parking for four wheeler in terms of linear ...

brainly.in/question/14142878

Find Y÷y+1=5÷12.linear equation chapter. - Brainly.in

brainly.in/question/7915928

the perimeter of a parallelogram is 40 cm write a linear equation in ...

brainly.in/question/9038755

Similar questions