Question

Ram buy a scooter at 13/15 of its value and sold it for 10% more than its value . his gain % is

Answer 1

Step-by-step explanation:

Let the cost price be ₹100

$\implies$ ${\Large\frac{13}{15}}×100$

$\implies$ ${\Large\frac{260}{3}}$

$C.P=\frac{260}{3}\\SP=110\\P=?$

$\implies$$P= SP-CP$

$\implies$ $P = 110 - \Large\frac{260}{3}$

$\implies$ $P=\Large\frac{330-260}{3}$

$\implies$ $P=\Large\frac{70}{3}$

$\implies$ Profit%$={\Large\frac{P}{CP}}×100$

$\implies$ Profit%$={\Large\frac{\Large\frac{70}{3}}{100}}×100$

$\implies$ Profit%$=\boxed{23\frac{1}{3}\: Percent}$

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Answer 2

let the value of scooter be x

CP of scooter be 13/15x

SP of scooter => x +x*10/100=>11/100

Gain => 11x/10-13x/15

=>33x-26x/30

=>-7x /30

Gain percentage =>/7x30/13x/15*100

=>7x /30*15/13x *100

=>380/3℅