Question

Ram buys 4 chairs nd 9 stools fr Rs1340 .If he sells chairs at 10% profit nd stools at 20% profit.he earns total profit of 188 Rs.How much money did he have to pay for the chairs

Answer 1

i think he bought 1070

Answer 2

Answer:

$800

Step-by-step explanation:

Let the cost of one chair be x

So, the cost of 4 chairs = 4x

Let the cost of 1 stool be y

So, the cost of 9 stools = 9y

Now we are given that cost of 4 chairs and 9 stools is Rs1340

So, equation becomes : $4x+9y=1340$   --1

He sells chairs at 10% profit and stools at 20% profit

Profit on 4 chairs : $10\% \times 4x$

                               $\frac{10}{100} \times 4x$

                               $0.4x$

Profit on 9 stools : $20\% \times 9y$

                               $\frac{20}{100} \times 9y$

                               $1.8y$

We are given that he earns total profit of Rs.188 .

So, Equation becomes:  $0.4x+1.8y=188$  --2

Solving 1 and 2 graphically

The intersection point will provide the solution

So, Intersection point = (200,60)

So, The cost of one chair is 200

So, cost of 4 chairs = $200 \times 4 =800$

Hence he paid $800 for chairs.