Math, asked by anupriya09, 1 year ago

Ram can do a piece of work in 8days which shyam can finish in 12days. if they work at it on alternate days with Ram beginning, in how many days the work will finished

Answers

Answered by harininneyveli
11

ram+shyam)'s 2 days work = (1/8+1/12) = 5/24

work done in 4 pair of days = (5/24)*4 = 5/6; remaining work = 1-(5/6) = 1/6

work done by ram on 9th day = 1/8; Remaining work = (1/6)-(1/8)= 1/24

On 10th day it is shyam's turn

1/12 work is done by shyam in 1 day

1/24 work is done by shyam in 12*(1/24) = 1/2

total time = (9 + 1/2) day

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