Math, asked by iamsweetjaya, 6 months ago


Ram has a box which contains cards bearing the numbers 1, 2, 3, .... 45. One card
is drawn randomly from the box, then the probability of getting a card bearing a
number divisible by 3 and 5 is

Answers

Answered by pardeepsingla80
0

Answer:

probability of getting a prime number=6/15=2/5

probability of getting a number divisible by 2= 7/15 ✓✓

Step-by-step explanation:

hope it will help u

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Answered by REDPLANET
60

\underline{ \boxed {\bold {Question}}}

  • Ram has a box which contains cards bearing the numbers 1, 2, 3, .... 45. One card  is drawn randomly from the box, then the probability of getting a card bearing a  number divisible by 3 and 5 is ___ ?

\underline{ \boxed {\bold {Important \: Concept \: To \: Be \: learned}}}

  • For a number divisible by 3 and 5 both, it should be multiple of 15. If number is not multiple of 15 then it won't be divisible by both 3 and 5.

\underline{ \boxed {\bold {Answer}}}

For finding probability we first need to find favorable events and total events possible.

Favorable Events = Multiple of 15 (From 1 to 45) = 3 events (15,30,45)

Total Events = 45 (1,2......44,45)

{ \boxed {\bold {\therefore Probability = \frac{Favourable \: Event}{Total \: Event}  }}}

∴ Probability = 3/45 = 1/15

Hope this helps u.../

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